HEREDITY
INCOMPLETE DOMINANCE
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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0%
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25%
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50%
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100%
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Detailed explanation-1: -So, the correct answer is ‘50%’.
Detailed explanation-2: -The colorblind father will transfer its carrier X chromosome to the daughter. The women will be a carrier for colorblindness XXc. The colorblind man will be XcY. The carrier female and color blind man will inherit the disease to 50% sons and 50% daughters.
Detailed explanation-3: -Since the female is a carrier, her genotype will be XhX. The male will be XY. Therefore there will be a 50% chance of the sons being colour blind and 50% chance of the sons being normal.
Detailed explanation-4: -A man needs only one copy of a defective gene to be colour blind. A woman needs two copies of defective genes to be colour blind. So when a colour blind man marries a normal sight woman all of their sons will be normal but their daughters will be carriers.
Detailed explanation-5: -Each daughter has a 50% chance for being color blind and a 50% chance for being a carrier.