CHILD DEVELOPMENT PEDAGOGY

GROWTH DEVELOPMENT CHILD

FORMATIVE ASSESSMENT

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
As a proton moves in a constant direction perpendicular to the electric field lines
A
it is moving from low potential to high potential and gaining electric potential energy.
B
it is moving from low potential to high potential and losing electric potential energy.
C
it is moving from high potential to low potential and gaining electric potential energy.
D
both its electric potential and electric potential energy remain constant.
Explanation: 

Detailed explanation-1: -The proton is moving from high potential to low potential and gaining electric potential energy. This means that it is moving from a high electric potential to a low electric potential.

Detailed explanation-2: -But, when the proton is set in the direction of the electric field, it starts to accelerate and as result, the speed of the proton also increases. This causes the kinetic energy to increase as well.

Detailed explanation-3: -The potential energy of a proton is 3. 2×10−18J at a particular point. The electric potential at this point is: (Given charge on a proton is 1.

Detailed explanation-4: -The statement is saying that if →E is perpendicular to d→r then q→E=→F will also be perpendicular to d→r, and so dW will be zero.

There is 1 question to complete.