CHILD DEVELOPMENT PEDAGOGY

GROWTH DEVELOPMENT CHILD

FORMATIVE ASSESSMENT

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
The 40 yards sprint times for a soccer team are found to be normally distributed with a mean of 5.2 seconds and a standard deviation of 0.3 seconds. What is the z-score for a player who runs a time of 5.6 seconds?
A
-1.33
B
1.33
C
0.88
D
1.02
Explanation: 

Detailed explanation-1: -The 40 yards sprint times for a soccer team are found to be normally distributed with a mean of 5.2 seconds and a standard deviation of 0.3 seconds. Then the value of the z-score approximately is 1.33.

Detailed explanation-2: -1 A distribution has a mean of 40 and a standard deviation of 5. Question: 68% of the distribution can be found between which two numbers? 68% of the distribution is within one standard deviation of the mean. 40 + 5 equals 45, 40-5 equals 35.

Detailed explanation-3: -The answer is ≈0.866 is the proportion of values within 1.5 standard deviations of the mean.

Detailed explanation-4: -The total area under the standard normal distribution curve is 1. Therefore, if we have a Z score, i.e., how far a value is above or below the mean, we can determine the probability of a value less than or greater than that.

Detailed explanation-5: -All normal distributions are symmetric, unimodal, bell-shaped, and have their maximum at the mean=mode=median. All normal distributions are continuous and have asymptotic tails—never touching the x-axis. The standard normal distribution is sometimes called the unit normal distribution.

There is 1 question to complete.