GROWTH DEVELOPMENT CHILD
FORMATIVE ASSESSMENT
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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200 V
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50 V
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400 V
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100 V
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Detailed explanation-1: -At a distance of 2 m, the potential will be “400 Volt".
Detailed explanation-2: -So we can say: Thus, The Electric Field Intensity will be 100 V/m at a distance of 4 metres from the point charge. So, the answer is Option (c) 4 m.
Detailed explanation-3: -The electric potential at a distance of 4 m from a certain point charge is 200 V relative to infinity.
Detailed explanation-4: -The electric potential at a point at a distance of 2m from a point charge of ‘0.1mu C‘ is 450V.
Detailed explanation-5: -We observe that the product of potential and distance is constant (equal to 6). Therefore V2=6E, which is the required relation between ‘V’ and ‘E’. Note: Students should always remember that electric potential is a scalar quantity whereas the electric field is a vector quantity.