COMPILER DESIGN

LEXICAL ANALYSIS

REGULAR EXPRESSIONS AND FINITE AUTOMATA

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
Let u=’1101’, v=’0001’, then uv=11010001 and vu= 00011101.Using the given information what is the identity element for the string?
A
B
u-1v-1
C
v-1
D
u-1
Explanation: 

Detailed explanation-1: -2. Let u=’1101’, v=’0001’, then uv=11010001 and vu= 00011101. Using the given information what is the identity element for the string? Explanation: Identity relation: w = w = w, thus the one satisfying the given relation will be the identity element.

Detailed explanation-2: -1 Answer. The best I can explain: Type 3 refers to Regular Languages which is accepted by a finite automaton.

Detailed explanation-3: -A DFA can be constructed from an NFA through a general process called “subset construction.” In this process, all sets of states generated by an NFA for any input are considered as states for the DFA. Subset construction is a process for converting any NFA into a DFA and thus is applicable to string matching.

Detailed explanation-4: -6. String X is accepted by finite automata if . Explanation: If automata starts with starting state and after finite moves if reaches to final step then it called accepted.

Detailed explanation-5: -Explanation : The given DFA accepts all the binary strings such that they are divisible by 3 and 2. Thus, it can be said that it also accepts all the strings which is divisible by 6.

There is 1 question to complete.