COMPUTER SOFTWARE
PROGRAMMING LANGUAGES
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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How many bytes are needed for an array of 1, 000 integers if each integer requires 32 bits of storage?
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1, 000 bytes
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4, 000 bytes
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16, 000 bytes
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32, 000 bytes
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Explanation:
Detailed explanation-1: -In 32-bit operating systems, the int type is usually 32 bits, or 4 bytes.
Detailed explanation-2: -You could find the first power of 2 that’s larger than your number, and divide that power by 8, then round the number up to the nearest integer. So for 1000, the power of 2 is 1024 or 2^10; divide 10 by 8 to get 1.25, and round up to 2. You need two bytes to hold 1000!
Detailed explanation-3: -By applying the formula, we find that the number of bits required in the address is 36 bits. This result highlights the importance of memory addressing in computer architecture, as large memories require a large number of bits to address each individual byte.
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