Consider an instance of TCPs Additive Increase Multiplicative Decrease (AIMD) algorithm where the window size at the start of the slow start phase is 1 MSS and the threshold at the start of the first transmission is 8 MSS. Assume that a timeout occurs during the sixth transmission. Find the congestion window size at the end of the 12th transmission.

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Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]

Consider an instance of TCP’s Additive Increase Multiplicative Decrease (AIMD) algorithm where the window size at the start of the slow start phase is 1 MSS and the threshold at the start of the first transmission is 8 MSS. Assume that a timeout occurs during the sixth transmission. Find the congestion window size at the end of the 12th transmission.

A	6
B	7
C	8
D	9

Explanation:

Detailed explanation-1: -In the slow-start phase the window size starts from 1 and grows exponentially until it reaches the threshold. After it reaches the threshold, the congestion avoidance (additive increase) procedure allows the window size to increase linearly until a timeout occurs or the maximum window size is reached.

Detailed explanation-2: -Correct Option: C During 10th transmission, it transmits 7 segments hence at the end of the 10th transmission the size of congestion window is 7 MSS.

Detailed explanation-3: -An intuitive explanation for why TCP decreases the window aggressively and increases it conservatively is that the consequences of having too large a window are compounding. This is because when the window is too large, packets that are dropped will be retransmitted, making congestion even worse.

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