COMPUTER SCIENCE AND ENGINEERING
COMPUTER ARCHITECTURE
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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1024
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4096
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248
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16, 777, 216
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Detailed explanation-1: -Since we have 24-bit addresses and address resolution is at the byte level, 224 bytes can be addressed. Then, words are there in address space = 2 24 2 4 = 220 = 1M words can be addressed. Hence the correct answer is 1 M words.
Detailed explanation-2: -24-bit addressing involves computers that can locate memory addresses that are 24-bits (3 bytes) wide, allowing for a theoretical maximum of 16 megabytes of memory, though logic board configurations may add other limitations.
Detailed explanation-3: -For an ānā bit address line, we can access 2n memory locations. So, n = 14 bits.
Detailed explanation-4: -On a 32-bit system, virtual addresses are 32 bits, which means that the virtual address space runs from 0 to 0xffff ffff. The size of this address space is 232 bytes, or 4 GiB. On a 64-bit system, the size of the virtual address space is 264 bytes, or 24ā 10246 bytes.