MCQ IN COMPUTER SCIENCE & ENGINEERING

COMPUTER SCIENCE AND ENGINEERING

SQL

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
How many 3 digits numbers can be formed using the digits 1, 2, 3, 4, 5, 7, 9.
A
343
B
464
C
565
D
666
Explanation: 

Detailed explanation-1: -Explanation: The first digit of the 3-digits can take 7 distinct values: 1, 2, 3, 4, 5, 7, 9. As repetition is allowed, the second digit can also take 7 distinct values, and the third can take 7 distinct values aswell, giving a total of 7⋅7⋅7=343 distinct combinations of numbers.

Detailed explanation-2: -∴ Total number of 3-digit numbers = 3×4×5=60.

Detailed explanation-3: -Therefore 120 such numbers are possible.

Detailed explanation-4: -There are 9 digits available to form 3-digits numbers without repetition. There are 9 choices for the hundreds digit, 8 choices for the tens digit, and 7 choices for the units digit. Therefore, 9 * 8 * 7 = 504 such 3-digits are possible.

Detailed explanation-5: -ANSWER: 120 three-digit numbers can be formed WITHOUT REPETITION OF DIGITS.

There is 1 question to complete.