ECONOMICS (CBSE/UGC NET)

ECONOMICS

COMPOUND INTEREST

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
Suppose a culture of bacteria begins with 5000 cells and dies by 30% each year. Write an equation that represents this situation.
A
y=5000(0.7)x
B
y=30(5000)x
C
y=5000(1.3)x
D
y=5000xx
Explanation: 

Detailed explanation-1: -A bacteria culture starts with 500 bacteria and grows at a rate proportional to its size. After 3 hours, there are 8000 bacteria. dP dt = kP. dP dt = ln(2)500 · 2t = ln(2)P, so the relative growth rate is ln (2).

Detailed explanation-2: -Thus, the population of the fish is 4309 .

Detailed explanation-3: -To find the amount for any time period, multiply the time period by the decay rate and raise e, the natural logarithm base, to the power of the result. Then take that answer and multiply it by the initial value.

Detailed explanation-4: -P1dtdP=−k. Here, the negative sign is the indication of decay. Then one of the solutions of this differential equation is P t = e − k t P t = e^-kt Pt=e−kt where, k is the relative decay rate.

There is 1 question to complete.