EVERYDAY SCIENCE

SCIENCE

CELL BIOLOGY

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
An animal cell placed in a hypertonic (salty) solution will
A
Stay the same
B
Shrink-get smaller
C
Swell-get bigger
D
None of the above
Explanation: 

Detailed explanation-1: -In a hypertonic solution, the net movement of water will be out of the body and into the solution. A cell placed into a hypertonic solution will shrivel and die by a process known as plasmolysis.

Detailed explanation-2: -When an animal cell is placed in a hypertonic solution, then water moves out of the cell as a result of exosmosis. So, when an animal cell will be placed in a hypertonic solution then it would lose water and shrink.

Detailed explanation-3: -If a cell is placed in a hypertonic solution, there will be a net flow of water out of the cell, and the cell will lose volume. A solution will be hypertonic to a cell if its solute concentration is higher than that inside the cell, and the solutes cannot cross the membrane.

Detailed explanation-4: -When a cell placed in hypertonic solution (has more solutes that cell), the cell will shrink because water moves out, firstly from the cytoplasm and then from the vacuole. This process is called as exosmosis which leads to the plasmolysis.

Detailed explanation-5: -If animal and plant cells are kept in a hypotonic solution then endosmosis will occur. Endosmosis is a process in which the water molecules move from outside of the cell of lower solute concentration to the inside of the cell of higher solute concentration through the cell membrane or cell wall.

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