EVERYDAY SCIENCE

SCIENCE

CHEMISTRY

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
Calculate the mass of oxygen present in a 55g sample of Aluminum oxide, Al2O3.
A
29.28
B
19.95
C
11.36
D
32.33
Explanation: 

Detailed explanation-1: -In the chemical formula of this compound, there are 3 atoms of oxygen, i.e., 1 mole of aluminum oxide contains 3 moles of oxygen.

Detailed explanation-2: -1 Expert Answer The molar mass of oxygen is 15.999 g/mol. Therefore, the molar mass of Al2O3 is 2(26.982 g/mol) + 3(15.999 g/mol) = 101.961 g/mol. The percent aluminum in Al2O3 is 100% * 2(26.982 g/mol) / 101.961 g/mol = 52.926%.

Detailed explanation-3: -This volume is known as molar volume. Hence, molar volume of a gas is defined as the volume occupied by one mole of a gas at S.T.P. Therefore; Mass of one molecule of oxygen = (32.0/ 6.022 × 1023) = 5.314 × 10-23 gram. Hence; Mass of one molecule of oxygen is 5.314 × 10-23 gram.

Detailed explanation-4: -Molecular weight of Al2O3=102g. Weight of Al in Al2O3=2×27=54g. Amount of Al in 102g of Al2O3=54g. Amount of Al in 9000g of Al2O3=10254×9000=4764. 7g.

There is 1 question to complete.