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Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
Using combustion reaction of hydrocarbon, empirical formula of hydrocarbon is found as CH2O . If the molar mass of hydrocarbon is 180g/mol what is the molecular formula of the hydrocarbon? (C:12g/mol, H:1g/mol, O:16g/mol)
A
C12H24O12
B
C8H16O8
C
C6H12O6
D
C3H6O3
Explanation: 

Detailed explanation-1: -Thus, for empirical formula CH2O and molecular mass 180 , molecular formula is C6H12O6.

Detailed explanation-2: -Molar mass is 120 g/mole which is 4 times 30, so 4 times CH2O is C4H8O4.

Detailed explanation-3: -The correct answer is C6H12O6. The compound using the proven formula CH2O has a vapour density of 90. The molecular formula of the compound is C6H12O6.

Detailed explanation-4: -Hence, molecular formula=2×CH2O=C2H4O2.

There is 1 question to complete.