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Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
What is the equation to show what happens to chloride ions at the anode.
A
Cl
B
2Cl
C
Cl2 + 2e-2Cl-
D
Cl2 + 2e
Explanation: 

Detailed explanation-1: -Is Cl2 + 2e → 2Cl − Cl2 + 2e → 2Cl− an oxidation half-reaction? In this example, the chlorine gas (Cl2Cl2) gains two electrons, bringing the oxidation state of 0 to an oxidation state of chloride ions to be-1. The charge here reduced, meaning this is a reduction half-reaction, NOT an oxidation reaction.

Detailed explanation-2: -At the anode The negative ions, chloride and hydroxide, are attracted to the positively charged anode. It is easier to oxidize hydroxide ions to oxygen than to oxidize chloride ions to chlorine, but there are far more chloride ions arriving at the anode than hydroxide ions.

Detailed explanation-3: -In the electrolysis of aqueous solution of NaCl typically, the major products at anode are Cl2 gas and O2 gas while those on cathode are H2 gas and Na metal. NaOH is also formed as a side product, which totally depends upon the concentration of NaCl in water.

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