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Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
What is the percent composition of a compound that contains 40.8 g carbon and 54.4 g oxygen?
A
42.9 % carbon; 57.1% oxygen
B
57.1 % carbon; 42.9 % oxygen
C
40.8 % carbon; 54.4 % oxygen
D
54.4 % carbon; 40.8% oxygen
Explanation: 

Detailed explanation-1: -%C=40.8⋅g95.2⋅g×100%=42.9% . %O=54.4⋅g95.2⋅g×100%=57.1% .

Detailed explanation-2: -The empirical formula is CH2O .

Detailed explanation-3: -Then we have 40.00 g of C, 6.72 g of H, and 53.28 g of O. The empirical formula is CH₂O.

Detailed explanation-4: -Percentage composition = 32/44 * 100 = 72.7 % (Answer)

Detailed explanation-5: -Molecular mass of CO2=1×12+2×16=44g. 1 g molecular of CO2=1×12+2×16=44g. ∴ % of C in CO2=1244×100=27.27%

There is 1 question to complete.