A 0.25-kg block is traveling along a horizontal, frictionless surface at a speed of 2.8 m/s. The block hits a wall and returns in the opposite direction at a speed of 1.7 m/s. What is the approximate impulse of the block on the wall?

PHYSICAL SCIENCES

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Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]

A	0.28 kg m/s
B	1.1 kg m/s
C	4.4 kg m/s
D	18 kg m/s

Explanation:

Detailed explanation-1: -A 1.5 kg block is initially at rest on a horizontal frictionless surface when a horizontal force along the x-axis is applied to the block. The force is given by F (x)=(2. 5−x2)i^ N, where x is in meters and the initial position of the block is x = 0.

Detailed explanation-2: -The speed of the block is 1.39 m/s when it passes the equilibrium position of the spring. The same experiment is now repeated with the frictionless surface replaced by a surface for which LK = 0.335.

Detailed explanation-3: -Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v2. If the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

Detailed explanation-4: -There are three different kinds of collisions, however, elastic, inelastic, and completely inelastic. Just to restate, momentum is conserved in all three kinds of collisions. What distinguishes the collisions is what happens to the kinetic energy.

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