SCIENCE
PHYSICAL SCIENCES
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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A1 = A2 = A3
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A1 = A2 + A3
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(A2 + A3) ˃ A1
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A2 ˂ A3˂ A1
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Detailed explanation-1: -Hence, the ammeter readings would be where A1 shows 1 ampere, A2 shows zero as bulb B2 blows off, A3 shows 1 ampere and A shows 2 amperes, the total current in the circuit.
Detailed explanation-2: -Reading in Ammeter A2 is 1.6 A. A3 = A1 + A2 = 2.4 + 1.6 = 4.0 A.
Detailed explanation-3: -The diode is reverse biased. Hence the resistance is infinite. So, current through A1 is zero. For A2, current =2/10=0.2 Amp.
Detailed explanation-4: -Expert-Verified Answer When bulb 2 gets fused: Reading on A1 is 1 ampere, reading on A2 is 0 ampere, reading on A3 1 ampere and reading on A is 2 ampere.
Detailed explanation-5: -V=IR, here V is the potential difference across a resistance R through which a current I is flowing. The ammeter is connected in series with the circuit. So its reading will show the value of the current flowing in the circuit. Hence, the reading of the ammeter is equal to 1A.