GEOLOGY
CRYSTALLOGRAPHY
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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relation between radius (r) of atom and size of cube (a) is
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a=r
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a=2r
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a=3r
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a=4r
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Explanation:
Detailed explanation-1: -The radius of the constituent particle of a simple cubic unit cell is equal to half of the edge length of the unit cell, i.e., r=12a.
Detailed explanation-2: -The relation between edge length (a) and radius of atom (r) for FCC lattice is √2a=4r.
Detailed explanation-3: -The relation between edge length (a) and radius of atom (r) for BCC lattice is √3a=4r .
Detailed explanation-4: -For the simple cubic unit cell, the atoms touch along the edge of the cube, so the edge length l is equal to twice the radius of the atom 2r.
There is 1 question to complete.