INDIAN HISTORY

HISTORY

MODERN INDIA

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Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]

At the historic Tripuri Session of the Congress (March 1939) Subhas Bose defeated Mahatma Gandhi’s official candidate for the Presidentship of the Congress. Who was Gandhiji’s nominee?

A	Abdul Kalam Azad
B	Jawaharlal Nehru
C	Pattabhi Sitaramayya
D	Vallabhbhai Patel

Explanation:

Detailed explanation-1: -In 1939, Bose put forward his name for presidentship of the Tripuri session. Mahatma Gandhi, on the other hand, put candidature of Pattabhi Sitaramayya. But the popularity of Bose shattered the hope of Gandhi and became the President.

Detailed explanation-2: -Tripuri is a small village in Madhya Predesh. In this session of Congress, Subhash Chandra Bose elected for the Presidentship of Indian National Congress.

Detailed explanation-3: -Pattabhi Sitaramayya was the closest candidate appointed by Mahatma Gandhi on his behalf. But he was defeated by Subhas Chandra Bose. Bose got a large number of votes as he was much popular among Indian people which made him win the election.

Detailed explanation-4: -In this session of Congress, Subhash Chandra Bose was elected for the Presidency of Indian National Congress. He won the elections by securing 1580 votes defeating Sitaramayya who secured 1377 votes, according to the results that were declared on 29 January, 1929.

There is 1 question to complete.