LIFE SCIENCE

Detailed explanation-1: -∙ Hence, the percentage of dominant individuals in next population = (64+32)% = 96%.

Detailed explanation-2: -Explanation: In Hardy-Weinberg equilibrium, the sum of the dominant allele frequency (p) and the recessive allele frequency (q) is equal to 1. The question says that 49% of the population consists of mice with the homozygous dominant gene, therefore, the dominant genotype frequency is equal to 0.49.

Detailed explanation-3: -To compute the frequency of recessive alleles, use the Hardy-Weinberg equilibrium equation. The recessive allele’s frequency is denoted by q, and it can be computed by taking the square root of q2.

Detailed explanation-4: -The Hardy-Weinberg Equation p = the frequency of the dominant allele in a population. q = the frequency of the recessive allele in a population. 2 p q 2pq 2pq = the frequency of the heterozygous dominant genotype. p 2 p^2 p2 = the frequency of homozygous dominant genotype.

Detailed explanation-5: -16% of the population shows the recessive phenotype, and therefore must carry the homozygous recessive genotype. We can use this information to solve for the recessive allele frequency.