OBJECTIVE LIFE SCIENCE
EVOLUTION
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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p2
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2pq
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q2
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p2 + 2pq
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Detailed explanation-1: -In the equation, p2 represents the frequency of the homozygous genotype AA, q2 represents the frequency of the homozygous genotype aa, and 2pq represents the frequency of the heterozygous genotype Aa.
Detailed explanation-2: -Answer: The frequency of heterozygous individuals is equal to 2pq. In this case, 2pq equals 0.32, which means that the frequency of individuals heterozygous for this gene is equal to 32% (i.e. 2 (0.8)(0.2) = 0.32).
Detailed explanation-3: -The second Hardy-Weinberg equation is used to determine genotype frequencies. Source. The variable ‘p2’ denotes the homozygous dominant genotype (AA), ‘2pq’ denotes the heterozygous genotype (Aa), and ‘q2’ denotes the homozygous recessive genotype (aa).
Detailed explanation-4: -Answer and Explanation: In Hardy Weinberg terms, 2Pq represents the frequency of the heterozygous individuals.
Detailed explanation-5: -The Hardy-Weinberg Equation p = the frequency of the dominant allele in a population. q = the frequency of the recessive allele in a population. 2 p q 2pq 2pq = the frequency of the heterozygous dominant genotype. p 2 p^2 p2 = the frequency of homozygous dominant genotype.