OBJECTIVE LIFE SCIENCE
MOLECULAR BIOLOGY
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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How many moles of KI are present in 0.85 L of a 0.55 M KI solution?
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3.10 mols
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0.935 mols
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0.4675 mols
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1.55 mols
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Explanation:
Detailed explanation-1: -How many moles of KI are present in 0.85 L of a 0.55 M KI solution? Therefore, there are 0.4675 moles of KI of 0.85L of a 0.55 M KI solution.
Detailed explanation-2: -What is the molarity of this solution? Therefore, an 0.85%w/v NaCl solution has a molarity of 0.14 mol/L.
Detailed explanation-3: -AI Recommended Answer: In this case, the weight is 60.0 g and the volume is 0.250 L, so the molarity is 60.0/0.250 or 12.5 M. To find out how much solution is required to provide 0.560 moles of NaOH, divide 12.5 M by 0.560 M to get 5.6 L of solution.
Detailed explanation-4: -Hence, the molarity of the solution is 0.5 M.
There is 1 question to complete.