NEET BIOLOGY

CELL STRUCTURES AND FUNCTION

CELL STRUCTURE

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
A wilted flower placed in a vase of water for several hours became stiff and stood erect. When it was placed in a salt solution, it wilted. From this information we can say that the cells of the flower are:
A
hypotonic to both fresh water and the salt solution.
B
hypertonic to both the fresh water and the salt solution.
C
hypertonic to fresh water but hypotonic to the salt solution.
D
hypotonic to fresh water but hypertonic to the salt solution.
Explanation: 

Detailed explanation-1: -A wilted flower placed in a vase of water for several hours became stiff and stood erect. When it was placed in a salt solution, it wilted. From this information we can say that the cells of the flower are: hypertonic to fresh water but hypotonic to the salt solution.

Detailed explanation-2: -When wilted flower is kept in fresh water, it revives because of passing of water through the cell wall to the flower resulting in revival of flower, this also happens because of osmosis.

Detailed explanation-3: -If a plant cell is placed in a hypertonic solution, the plant cell loses water and hence turgor pressure by plasmolysis: pressure decreases to the point where the protoplasm of the cell peels away from the cell wall, leaving gaps between the cell wall and the membrane and making the plant cell shrink and crumple.

Detailed explanation-4: -If a cell is placed in a hypertonic solution, water will leave the cell, and the cell will shrink. In an isotonic environment, there is no net water movement, so there is no change in the size of the cell. When a cell is placed in a hypotonic environment, water will enter the cell, and the cell will swell.

Detailed explanation-5: -A cell placed into a hypertonic solution will shrivel and die by a process known as plasmolysis. An isotonic solution is any external solution that has the same solute concentration and water concentration compared to body fluids.

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