NEET BIOLOGY

REPRODUCTION

EMBRYONIC DEVELOPMENT

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
What process does the zygote undergoe to become a blastula?
A
Cleavage
B
Gastrulation
C
Metamorphosis
D
Cephalization
Explanation: 

Detailed explanation-1: -The process of embryogenesis begins when an egg or ovum is fertilized by a sperm cell to form a zygote. This zygote then undergoes mitotic division, a process that does not result in any significant growth but creates a multicellular cluster called a blastula. This process is referred to as cleavage.

Detailed explanation-2: -After fertilization, the zygote undergoes cleavage to form the blastula. The blastula, which in some species is a hollow ball of cells, undergoes a process called gastrulation, in which the three germ layers form.

Detailed explanation-3: -Solution : Cleavage is a phase in embryogenesis, in which the single-celled zygote is converted into a multicellular structure morula then blastocyst. The cleavage divisions which are mitotic division start, when the zygote is still in fallopian tubes.

Detailed explanation-4: -Human zygote cleavage begins inside the fallopian tube. It is holoblastic, dividing the zygote fully into blastomeres or daughter cells. After fertilisation, the first cleavage occurs about 24 to 30 hours later. It creates two blastomeres by longitudinally dividing the zygote (one mildly larger than the other).

Detailed explanation-5: -The zygote is a single diploid cell, which will ultimately multiply through mitotic division to form a multicellular embryo. This mitotic division does not result in any significant growth and the multicellular cluster that is formed is the same size as the zygote. This cell division process is referred to as cleavage.

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