SOLAR SYSTEM

UNIVERSE

SATELLITESICY BODIES

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
According to Kepler, the orbital period of a planet is directly proportional to the
A
planet’s average distance from the Sun.
B
cube of the planet’s average distance from the Sun.
C
square of the planet’s average distance from the Sun.
D
None of the above
Explanation: 

Detailed explanation-1: -Kepler’s Third Law: the squares of the orbital periods of the planets are directly proportional to the cubes of the semi-major axes of their orbits. Kepler’s Third Law implies that the period for a planet to orbit the Sun increases rapidly with the radius of its orbit.

Detailed explanation-2: -Kepler’s third law : The square of its period of revolution around the Sun is directly proportional to the cube of the mean distance of a planet from the Sun.

Detailed explanation-3: -Kepler’s third law states that square of period of revolution (T) of a planet around the sun, is proportional to third power of average distance r between sun and planet i.e. T2=Kr3 where K is constant.

Detailed explanation-4: -The equation for Kepler’s Third Law is P² = a³, so the period of a planet’s orbit (P) squared is equal to the size semi-major axis of the orbit (a) cubed when it is expressed in astronomical units.

Detailed explanation-5: -Kepler’s 3rd Law of Periods: This law is known as the law of Periods. The square of the time period of the planet is directly proportional to the cube of the semimajor axis of its orbit.

Detailed explanation-6: -Kepler’s third law states that the square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.

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