UNIVERSE
SATELLITESICY BODIES
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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Calculate the linear speed of a satellite in an orbit 900 km above Earth’s surface. Given G = 6.67 x 10^-11 N m^2 kg^-2, radius of earth is 6370 km and mass of the earth is 5.97 x 10^24 kg.
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1.05 x 10^4 m s^-1
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2.97 x 10^4 m s^-1
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9.40 x 10^5 m s^-1
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7.40 x 10^3 m s^-1
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Explanation:
Detailed explanation-1: -As seen in the equation v = SQRT(G * Mcentral / R), the mass of the central body (earth) and the radius of the orbit affect orbital speed.
Detailed explanation-2: -D Calculate the speed of a satellite in an orbit at a height of 1000 km from the Earth’s surface. M=5.98x1024 kg, R = 6.4x10m. [Ans: 7.34 x10 m/s]
Detailed explanation-3: -Solution. Speed of the satellite at height 1000 km is 7.343 × 103 m/s.
There is 1 question to complete.