UNIVERSE
SATELLITESICY BODIES
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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Detailed explanation-1: -The escape velocity vesc is expressed as vesc = Square root of√2GMr, where G is the gravitational constant, M is the mass of the attracting mass, and r is the distance from the centre of that mass.
Detailed explanation-2: -The escape velocity is a multiplicative factor greater than the orbital velocity: v = sqrt(2GM/r) (escape velocity = sqrt(2) * orbital velocity) If an object achieves escape velocity, it leaves its orbit and is no longer gravitationally bound to the object it was orbiting.
Detailed explanation-3: -Escape velocity from the surface of earth is 11.2 km/s. Let ve be the escape velocity of the body on the surface of earth (of mass ME and Radius RE) and the mass of the body to be projected be m.
Detailed explanation-4: -The escape velocity of Earth is 11.19 km/s.