SOLAR SYSTEM

UNIVERSE

SATELLITESICY BODIES

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
You are making a circular turn in your car on a horizontal road when you hit a big patch of ice, causing the force of friction between the tires and the road to become zero. While the car is on the ice, it
A
continues to follow a circular path, but with a radius larger than the original radius.
B
moves along a straight-line path in its original direction.
C
moves along a straight-line path toward the center of the circle.
D
moves along a path that is neither straight nor circular.
E
moves along a straight-line path away from the center of the circle.
Explanation: 

Detailed explanation-1: -When the car moves along a circular path, it needs a centripetal force acting inwards to compensate for the centrifugal force acting outwards. This force is provided by the frictional force between tyres and road which will act towards the center of circular motion.

Detailed explanation-2: -The centripetal force causing the car to turn in a circular path is due to friction between the tires and the road. A minimum coefficient of friction is needed, or the car will move in a larger-radius curve and leave the roadway. We know that Fc=mv2r.

Detailed explanation-3: -If the car suddenly hits an icy road, then the coefficient of friction will be smaller which is directly proportional to the centripetal force. Hence, the friction will be greatly reduced, the centripetal force will be reduced, and the car will stop moving in a circular path but will make a straight path.

Detailed explanation-4: -Reason : The necessary centripetal force is provided by the force of friction between the tyres and the road.

Detailed explanation-5: -If there is friction between the tyres and road, the car will move. If there is no friction between the tyres and road, the car will not move.

There is 1 question to complete.