VISUAL BASIC

INTRODUCTION TO NET

APPLICATION DEVELOPMENT

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
Which rule availability setting can you use to force the system to look for an instance of the rule in the next highest class or ruleset?
A
Final
B
Available
C
Blocked
D
Withdrawn
Explanation: 

Detailed explanation-1: -Which rule availability setting can you use to force the system to look for an instance of the rule in the next highest class or ruleset? DS: When a rule marked as Withdrawn is found during rule resolution, the system looks for an instance of the rule in the next highest class or ruleset.

Detailed explanation-2: -A withdrawn rule is a rule that has the availability property pyRuleAvailable set to Withdrawn . A withdrawn rule is never selected by rule resolution. In addition, other rules that match this rule on the following fields are also hidden from rule resolution: Rule type.

Detailed explanation-3: -Pega Platform displays rule availability in brackets. In the Availability list, select an option to control how your application selects the rule during rule resolution: You cannot change the availability of some rule types, such as classes and rulesets, which are always available to users.

Detailed explanation-4: -The rule purpose takes precedence over the rule availability. If a user does not have access to the selected rule, the system sends a message that the rule is not authorized for execution.

Detailed explanation-5: -You can set the availability of a rule to one of five values: Available, Not Available, Blocked, Final, or Withdrawn. Note: For more information on ensuring the correct rule is used at run-time, see the Pega Community article Setting rule status and availability.

Detailed explanation-6: -Select an Availability value: Available. The Base Rule checkbox appears if rules of this rule type can be circumstance-qualified or time-qualified, but this rule itself is not qualified. For rules you have created in this system, leave this box cleared in most cases. Click Save .

There is 1 question to complete.