ANATOMY

Detailed explanation-1: -Since we already know which genotypes will produce offspring with freckles, we can see that three of the four potential offspring have a genotype that would produce freckles. So there’s a 75 percent probability that a couple who are both heterozygous for the allele for freckles will have a child who has freckles.

Detailed explanation-2: -If the trait for not having freckles is recessive, we know that the child would be homozygous recessive because the trait could only be expressed with two recessive alleles present. The mothers genotype would have to be “Ff” to produce a child who is homozgyous recessive (ff).

Detailed explanation-3: -Both the man and woman are heterozygous for freckles. This means both of their genotype is Ff and their phenotype is the expression of freckles.

Detailed explanation-4: -A monohybrid cross results in a phenotypic ratio of 3:1 (dominant to recessive), and a genotypic ratio of 1:2:1 (homozygous dominant to heterozygous to homozygous recessive).