BIOLOGY
STRUCTURE OF GLUCOSE
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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mild
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strong
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Either A or B
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None of the above
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Detailed explanation-1: -The bromine water test is a simple test to distinguish between glucose and fructose. The Glucose undergoes oxidation reaction to give glucuronic acid on reaction with the bromine water solution. Since bromine water is a mild oxidizing agent, fructose fails to undergo an oxidation reaction.
Detailed explanation-2: -An oxidizing agent is a compound that has the ability to oxidize other compounds, causing them to lose electrons and hence raise their oxidation state. Mild oxidizing agents do not convert alcohol to carboxylic acids entirely. However, the reaction will stop at ketone.
Detailed explanation-3: -Ag2O is a mild oxidizing agent.
Detailed explanation-4: -Similarly, bromine is a more powerful oxidizing agent than iodine. Bromine can remove electrons from iodide ions, producing iodine; iodine cannot reclaim those electrons from the resulting bromide ions.
Detailed explanation-5: -Since, Bromine has a larger atomic radius, the nuclear force of attraction on the electrons is less and hence Bromine can easily give away its valence electrons. Thus Bromine is a stronger reducing agent than Chlorine.