BIOMOLECULES AND ENZYMES

Detailed explanation-1: -Option A: n-Hexane: Glucose in the presence of red phosphorus is when heated with HI – hydroiodic acid, it gives n-hexane. This shows that glucose has a straight six-carbon chain.

Detailed explanation-2: -Answer. Glucose on prolonged heating with hydroiodic acid (HI) in the presence of red Phosphorus results in the formation of n-hexane. Formation of n-hexane indicates that all the six carbon atoms in glucose are linked in a straight chain.

Detailed explanation-3: -On prolonged heating with HI, glucose gives n-hexane.

Detailed explanation-4: -Hot hydriodic acid (HI) was often used to reductively remove oxygen functional groups from a molecule, and in the case of glucose this treatment gave hexane (in low yield). Glucose is reduced with concentrated hydriodic acid in the presence of red phosphorus to form a trace amount of n-hexane.