CHILD DEVELOPMENT PEDAGOGY

GROWTH DEVELOPMENT CHILD

HEREDITY AND ENVIRONMENT

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
If you cross two heterozygous traits (Rr x Rr), as Mendel did in his second experiment, what ratio will you get between offspring with the dominant and recessive phenotypes
A
1:1
B
2:1
C
3:1
D
4:1
Explanation: 

Detailed explanation-1: -Explanation: When crossing organisms that are heterozygous for two traits, the result is a dihybrid cross. The phenotypic ratio of a heterozygous dihybrid cross for autosomal (none-sex-linked) traits is always 9:3:3:1. Nine offspring will show both dominant traits (AABB, AaBB, AABb, AaBb).

Detailed explanation-2: -Answer and Explanation: If two heterozygous individuals are crossed, then the phenotypic ratio of the offspring would be 3:1(dominant:recessive).

Detailed explanation-3: -Because heterozygotes could arise from two different pathways (receiving one dominant and one recessive allele from either parent), and because heterozygotes and homozygous dominant individuals are phenotypically identical, the law supports Mendel’s observed 3:1 phenotypic ratio.

Detailed explanation-4: -SEE A PATTERN FOR HETEROZYGOUS MONOHYBRID CROSSES: If you cross 2 parent plants that are BOTH HETEROZYGOUS for a trait the offspring will show a 3:1 phenotypic ratio.

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