SSC MTS EXAM

SSC

CHEMISTRY

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
Number of moles present in 22.0g of carbondioxide is
A
2
B
22
C
0.5
D
0.25
Explanation: 

Detailed explanation-1: -Then, 22 g of carbon dioxide =2244 mole = 0.5 mole.

Detailed explanation-2: -Give that 20 g of water. =20 / 18=1.111 mole. Give that 22 g of carbon dioxide. =22 / 44=0.5 mole.

Detailed explanation-3: -thus in 0.5 moles there are 2 / 2 = 1 mole of oxygen in 22g (0.5 moles) of CO2.

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