SSC MTS EXAM

SSC

CHEMISTRY

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
Propene is converted to propanone in a two stage process.Propene
A
CH3CHBrCH3
B
CH3CH2CH2Br
C
CH3CHOHCH3
D
CH3CH2CH2OH
Explanation: 

Detailed explanation-1: -Propan-1-ol can also be produced through the hydroboration oxidation reaction. In this, Alkene reacts with diborane (BH3)2 with propene to produce trialkyl boranes which are then oxidized to propan-1-ol by peroxide in the presence of NaOH.

Detailed explanation-2: -The conversion of Propene to Propan-2-ol can be explained using Markovnikov’s rule. Propene in presence of acid and water produces propan-2-ol. When Propene undergoes a reaction with water in the presence of an acid as a catalyst, we obtain the Markovnikov’s product, Propan–2–ol.

Detailed explanation-3: -Step 1: Formation of Propan-2-ol. Propanone is treated with Lithium Aluminium hydride which acts as a reducing agent and reduces the ketone group to a alcohol. The product formed is Propan-2-ol. Step 2: Formation of Propene. The Propan-2-ol so formed now is treated with concentrated Sulphuric acid at .

There is 1 question to complete.