SSC
CHEMISTRY
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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CH3CHBrCH3
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CH3CH2CH2Br
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CH3CHOHCH3
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CH3CH2CH2OH
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Detailed explanation-1: -Propan-1-ol can also be produced through the hydroboration oxidation reaction. In this, Alkene reacts with diborane (BH3)2 with propene to produce trialkyl boranes which are then oxidized to propan-1-ol by peroxide in the presence of NaOH.
Detailed explanation-2: -The conversion of Propene to Propan-2-ol can be explained using Markovnikov’s rule. Propene in presence of acid and water produces propan-2-ol. When Propene undergoes a reaction with water in the presence of an acid as a catalyst, we obtain the Markovnikov’s product, Propan–2–ol.
Detailed explanation-3: -Step 1: Formation of Propan-2-ol. Propanone is treated with Lithium Aluminium hydride which acts as a reducing agent and reduces the ketone group to a alcohol. The product formed is Propan-2-ol. Step 2: Formation of Propene. The Propan-2-ol so formed now is treated with concentrated Sulphuric acid at .