SSC
CHEMISTRY
| Question 
 [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
 | 
|  |  CH3CHBrCH3 
 | 
|  |  CH3CH2CH2Br 
 | 
|  |  CH3CHOHCH3 
 | 
|  |  CH3CH2CH2OH 
 | 
Detailed explanation-1: -Propan-1-ol can also be produced through the hydroboration oxidation reaction. In this, Alkene reacts with diborane (BH3)2 with propene to produce trialkyl boranes which are then oxidized to propan-1-ol by peroxide in the presence of NaOH.
Detailed explanation-2: -The conversion of Propene to Propan-2-ol can be explained using Markovnikov’s rule. Propene in presence of acid and water produces propan-2-ol. When Propene undergoes a reaction with water in the presence of an acid as a catalyst, we obtain the Markovnikov’s product, Propan–2–ol.
Detailed explanation-3: -Step 1: Formation of Propan-2-ol. Propanone is treated with Lithium Aluminium hydride which acts as a reducing agent and reduces the ketone group to a alcohol. The product formed is Propan-2-ol. Step 2: Formation of Propene. The Propan-2-ol so formed now is treated with concentrated Sulphuric acid at .