SSC MTS EXAM

SSC

CHEMISTRY

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
What is the percent composition of a compound that contains 40.8 g carbon and 54.4 g oxygen?
A
42.9 % carbon; 57.1% oxygen
B
57.1 % carbon; 42.9 % oxygen
C
40.8 % carbon; 54.4 % oxygen
D
54.4 % carbon; 40.8% oxygen
Explanation: 

Detailed explanation-1: -%C=40.8⋅g95.2⋅g×100%=42.9% . %O=54.4⋅g95.2⋅g×100%=57.1% .

Detailed explanation-2: -Mass percentage is calculated as the mass of a component divided by the total mass of the mixture, multiplied by 100.-We know that the atomic weight of carbon is 12 grams and that of oxygen is 16 grams. Hence we have calculated the mass 5 of carbon in carbon dioxide to be 27.27%.

Detailed explanation-3: -Percentage composition = 32/44 * 100 = 72.7 % (Answer)

Detailed explanation-4: -Hence the empirical formula is C₂H₄O.

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