SSC MTS EXAM

SSC

PHYSICAL GEOGRAPHY

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
The Tropic of Cancer is located at ____ degrees North Latitude.
A
23.5
B
66.5
C
0
D
90
Explanation: 

Detailed explanation-1: -The Tropic of Cancer is a parallel of latitude on the Earth, 23.5 degrees north of the equator. On the northern summer solstice/southern winter solstice (around the 21st June each year), the Sun reaches its most northerly declination of +23.5 degrees.

Detailed explanation-2: -The earth is tilted at an angle of 23 degrees and 27 minutes with respect to its orbital plane (Figure 1). This tilt is termed the earth’s declination. At noon on June 21 the sun is directly perpendicular to the earth’s surface at 23.5° north. This is the reason the Tropic of Cancer is marked on a globe.

Detailed explanation-3: -The Tropic of Cancer is a parallel of latitude on the earth, 23.5 degrees north of the equator. It passes through 8 Indian states: Gujarat, Rajasthan, Madhya Pradesh, Chhattisgarh, Jharkhand, West Bengal, Tripura, Mizoram.

Detailed explanation-4: -The Tropic of Cancer lies at 23d 26’ 22” (23.4394 degrees) north of the Equator and marks the most northerly latitude at which the sun can appear directly overhead at noon.

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