SSC MTS EXAM

SSC

PHYSICS

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
A ball has a 17 J of kinetic energy and its mechanical energy is 25 J. If the ball has a mass of 3.2 kg, what is its height above the ground?
A
0.26 m
B
0.52 m
C
5.2 m
D
25 m
Explanation: 

Detailed explanation-1: -The total mechanical energy of the ball is E=25 J E = 25 J . The kinetic energy at the said point is Ek=17 J E k = 17 J . The gravitational potential energy Eg equals the total mechanical energy of the system minus the kinetic energy, i.e. The potential energy of the ball is 8 Joules.

Detailed explanation-2: -H is equal to this is 989800. That means it is 9800 divided by 9.8, which means 1000 point. So this h is equal to 1000 divided by 56, and when you divide this number, you get what the sight is equal to 17.85 over 86.

Detailed explanation-3: -How much kinetic energy does a 1.2 kg ball have the moment it hits the ground 3.5 meters below when it starts from rest? I cancelled out the initial kinetic energy because: KEi = ½ mv. KEi = (½)(3.5)(02) = 0 J.

There is 1 question to complete.