SSC MTS EXAM

SSC

PHYSICS

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
A box takes 40 N to start moving when the coefficient of static friction is .54. What is the weight of the box?
A
81 N
B
18 N
C
98 N
D
74 N
Explanation: 

Detailed explanation-1: -Hence, weight of the box is 74.08 kg.

Detailed explanation-2: -The coefficient of friction (fr) is a number that is the ratio of the resistive force of friction (Fr) divided by the normal or perpendicular force (N) pushing the objects together. It is represented by the equation: fr = Fr/N.

Detailed explanation-3: -The coefficient of static friction between a 40.0-kg picnic table and the ground below it is 0.43.

There is 1 question to complete.