SSC
PHYSICS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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A particle is moving in a circular path of radius r.The displacement after half a circle would be:
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Zero
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r
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2r
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2r
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Explanation:
Detailed explanation-1: -Now, coming to question, we have a particle which has travelled half the circle and we have to find the displacement. Initial position of the particle is B and the final position of the particle is A. Therefore, the shortest distance between A and B is 2r. Hence, displacement = 2r.
Detailed explanation-2: -The displacement of a particle moving in a circular path is given by =3t2+0.8, where is in radian and t is in seconds . The angular velocity of the particle at t=3 sec .
Detailed explanation-3: -In half the period of revolution, displacement will be 2R and distance covered will be R. Was this answer helpful?
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