SSC
PHYSICS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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A particular light bulb is 23% efficient. If 200 kJ of energy is put into the light bulb, the amount of energy the light is producing is
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200 KJ
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46 KJ
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870 KJ
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4600 KJ
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Explanation:
Detailed explanation-1: -equation : E = m ×c × to determine the thermal energy so that we could subtract this from 100 to estimate the efficiency of the light energy of the bulbs.
Detailed explanation-2: -Answer and Explanation: A 100-watt light bulb uses 100 joules of energy per second, by definition of a watt. Since there are 60 seconds in a minute and 60 minutes in an hour, there are 3600 seconds in an hour.
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