SSC
PHYSICS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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A projectile is launched from the ground at an angle of 30o. At what point in its trajectory does this projectile have the least speed?
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just after it is launched
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at the highest point in its flight
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just before it hits the ground
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halfway between the ground and the highest point
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speed is always constant
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Explanation:
Detailed explanation-1: -a ball is hit at an angle of 30°. At what point in its trajectory does this projectile have the least speed? Explanation: The velocity of the projectile at highest point is 0 m/s.
Detailed explanation-2: -The range of a projectile launched at angle of 30∘ to the horizontal is 1km .
Detailed explanation-3: -Horizontal range = R=gu2sin2=1030×30×2sin60∘cos60∘=453 m.
Detailed explanation-4: -The highest point in any trajectory, called the apex, is reached when vy = 0. Since we know the initial and final velocities, as well as the initial position, we use the following equation to find y: v2y=v20y−2g(y−y0).
There is 1 question to complete.