SSC MTS EXAM

SSC

PHYSICS

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
Acceleration is calculated using the following formula:
A
a = (u-v) / t
B
a = t / ( v-u)
C
a = t (u-v) / t
D
a = (v-u) / t
Explanation: 

Detailed explanation-1: -The correct answer is (v-u)/t. CONCEPT: Acceleration: The rate of change in velocity is called acceleration.

Detailed explanation-2: -The “suvat” Equations Acceleration is the rate of change of velocity of an object. where a is acceleration, v is the final velocity of the object, u is the initial velocity of the object and t is the time that has elapsed.

Detailed explanation-3: -As before, v = final speed, u = initial speed, a = acceleration, s = distance travelled.

Detailed explanation-4: -a = (v f-v i) / t; a = 2 × (d-v i × t) / t²; a = F / m; 02-Feb-2023

There is 1 question to complete.