SSC MTS EXAM

SSC

PHYSICS

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
De Broglie equation
A
relates the momentum of a mass to its wavelength
B
relates the energy of a mass to its wavelength
C
relates the frequency of a mass to its wavelength
D
relates the work function of a mass to its wavelength
Explanation: 

Detailed explanation-1: - = h m v = h momentum : where ‘h’ is the Plank’s constant. This equation relating the momentum of a particle with its wavelength is the de Broglie equation, and the wavelength calculated using this relation is the de Broglie wavelength.

Detailed explanation-2: -He postulated that a wavelength could be associated with a particle once you know its mass and its velocity. The deBroglie wavelength is defined as follows: lambda = h/mv, where the greek letter lambda represents the wavelength, h is Planck’s contant, m is the particle’s mass and v is its velocity.

Detailed explanation-3: -Thus depends only on mass of particle, velocity of particle and its momentum but not on its charge.

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