SSC
PHYSICS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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Disk Y of rotational inertia
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The angular momentum of disk X immediately after the collision is greater than the angular momentum of disk X immediately before the collision.
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The angular momentum of disk Y immediately after the collision is greater than the angular momentum of disk Y immediately before the collision.
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The angular momentum of disk Y immediately after the collision is greater than the angular momentum of the disk X-disk Y system immediately before the collision.
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The angular momentum of the disk X-disk Y system immediately after the collision is equal to the angular momentum of the system immediately before the collision.
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Explanation:
Detailed explanation-1: -In rotational motion, the rotational inertia formula is I=mr2 I = m r 2 or simply I=mr2 I = m r 2, where m is the mass and r is the radius or the distance between the concentration of mass from the axis of rotation.
Detailed explanation-2: -The moment of inertia of a hoop is its mass times its radius squared (mr2). The moment of inertia of a disk is ½ its mass times its radius squared (½mr2). The linear velocity of a rolling disk is twice the linear velocity of a hoop of equal mass.
Detailed explanation-3: -Using theorem axes, moment of inertia of the disc passing through a point on its edge and normal to the disc =21MR2+MR2=23MR2.
There is 1 question to complete.