SSC MTS EXAM

SSC

PHYSICS

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
For Hooke’s Law, F = kx, where:
A
F = force, k = a constant, x = speed
B
F = force, k = a constant, x = extension
C
F = force, k = the spring constant constant, x = speed
D
F = friction, k = spring value, x = speed
Explanation: 

Detailed explanation-1: -W = kx. W is the weight of the added mass. Therefore, the spring constant k is the slope of the straight line W versus x plot. Weight is mass times the acceleration of gravity or W = mg where g is about 980 cm/sec2.

Detailed explanation-2: -Where F is the force, x is the length of extension/compression and k is a constant of proportionality known as the spring constant which is usually given in N/mstart text, N, slash, m, end text.

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