SSC MTS EXAM

SSC

PHYSICS

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
Power of the lens is-40, its focal length is
A
4m
B
-40m
C
-0.25m
D
-25m
Explanation: 

Detailed explanation-1: -Here, P is the power of the lens and f is the focal length of the lens in meter (m). Given, P =-40 D. f =-0.025 m. Thus, the focal length of the lens is-0.025 m.

Detailed explanation-2: -The correct answer is option 4, i.e.-2.5 D. The Power of the diverging lens is-2.5 D.

Detailed explanation-3: -The power of a lens is defined as the reciprocal of its focal length in meters, or D=1f, where D is the power in diopters and f is the focal length in meters. Lens surface power can be found with the index of refraction and radius of curvature.

There is 1 question to complete.