SSC MTS EXAM

SSC

PHYSICS

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
The equation for PE (gravitational potential energy) is:
A
mgh2
B
mgh
C
1/2mgh
D
1/2mv2
Explanation: 

Detailed explanation-1: -The formula for potential energy depends on the force acting on the two objects. For the gravitational force the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters.

Detailed explanation-2: -Let’s consider an object taken to a height ‘h’ from the surface of the earth. When, h«R, then, R + h = R and g = GM/R2. On substituting this in the above equation we get, Gravitational Potential Energy U = mgh.

Detailed explanation-3: -If the object is lifted straight up at constant speed, then the force needed to lift it is equal to its weight mg. The work done on the mass is then W = Fd = mgh. We define this to be the gravitational potential energy (PEg)put into (or gained by) the object-Earth system.

Detailed explanation-4: -The value of gravitational potential is given by, V =-GM/R.

There is 1 question to complete.