SSC MTS EXAM

SSC

PHYSICS

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
What is the coefficient of static friction if it takes 44 N of force to move a box that weighs 86 N?
A
0.78
B
0.51
C
0.78 N
D
0.58 N
Explanation: 

Detailed explanation-1: -so, an object of weight 86N is opposed by a frictional force of 44N. Henceforth, the coefficient of static friction is 0. 51.

Detailed explanation-2: -Given, mass m = 100 kg. Given, F=98N. Therefore, the coefficient of friction is, =0.1. Hence, the correct option is Option D.

Detailed explanation-3: -Now, the net frictional force at limiting conditions: Now, the question says that the 40 kgf force is just enough to move the body: So, coefficient of static friction between block and surface is 0. 1 .

There is 1 question to complete.