BIOMOLECULES AND ENZYMES

BIOLOGY

NUCLEIC ACIDS

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
DNA sequence is ACAGTGC. How would this be coded on mRNA?
A
TGTCACG
B
UGUCACG
C
GUGACAU
D
CACUGUA
Explanation: 

Detailed explanation-1: -The DNA sequence ACAGTGC would be coded as—UGUCACG.

Detailed explanation-2: -DNA utilizes four bases, adenine (A), guanine (G), cytosine (C), and thymine (T), in its code. RNA also uses four bases. However, instead of using ‘T’ as DNA does, it uses uracil (U). Therefore, if your DNA sequence is 3’ T C G T T C A G T 5’, the mRNA sequence would be 5’ A G C A A G U C A 3’.

Detailed explanation-3: -During transcription, the enzyme RNA polymerase (green) uses DNA as a template to produce a pre-mRNA transcript (pink). The pre-mRNA is processed to form a mature mRNA molecule that can be translated to build the protein molecule (polypeptide) encoded by the original gene.

Detailed explanation-4: -When a DNA strand with the sequence AACGTAACG is transcribed, the resultant sequence of the mRNA molecule synthesized is UUGCAUUGC. This is based on the paring of nitrogenous bases-adenine pairs with thymine (in DNA) and uracil (in RNA) and guanine with cytosine.

Detailed explanation-5: -Answer: Four amino acids can be coded for by this message.

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